[프로그래머스] 09/25 (2)

[숫자 문자열과 영단어]-[2021 카카오 채용연계형 인턴십]

My answer

def solution(s):
    code=["zero","one","two","three","four","five","six","seven","eight","nine"]
    answer,tmp = "", ""
    for i in range(len(s)):
        if(s[i].isdigit()):
            answer+=s[i]
        else:
            tmp+=s[i]
        if(tmp!="" and tmp in code):
            for i in range(len(code)):
                if(tmp==code[i]):
                    answer+=str(i)
                    tmp=""
    return int(answer)

Another answer

num_dic = {"zero":"0", "one":"1", "two":"2", "three":"3", "four":"4", "five":"5", "six":"6", "seven":"7", "eight":"8", "nine":"9"}

def solution(s):
    answer = s
    for key, value in num_dic.items():
        answer = answer.replace(key, value)
    return int(answer)

[신규 아이디 추천]-[2021 KAKAO BLIND RECRUITMENT]

My answer

def solution(new_id):
    answer = ''
    #1단계-------------------------
    new_id=new_id.lower()
    #2단계-------------------------
    for i in new_id:
        if (i.isalnum()==0 and i!='-' and i!='_' and i!='.'):
            new_id=new_id.replace(i,"")
    #3단계-------------------------
    for i in range(len(new_id)):
        if(new_id[i].isalnum()==0 and i!=0 and new_id[i]=='.' and (new_id[i-1]=='.' or new_id[i-1]=='@')):
            new_id=new_id[:i]+'@'+new_id[i+1:]
    new_id=new_id.replace("@","")
    #4단계--------------------------
    if(len(new_id)!=0 and new_id[0]=='.'):
        new_id=new_id[1:]
    if(len(new_id)!=0 and new_id[-1]=='.'):
        new_id=new_id[:-1]
    #5단계--------------------------
    if(new_id==""):
        new_id='a'
    #6단계--------------------------
    if(len(new_id)>=16):
        new_id=new_id[:15]
    if(new_id[-1]=='.'):
        new_id=new_id[:-1]
    #7단계---------------------------
    if(len(new_id)<=2):
        while(len(new_id)<3):
            new_id+=new_id[-1]
            
    answer=new_id
    
    return answer

Another answer

import re

def solution(new_id):
    st = new_id
    st = st.lower()
    st = re.sub('[^a-z0-9\-_.]', '', st)
    st = re.sub('\.+', '.', st)
    st = re.sub('^[.]|[.]$', '', st)
    st = 'a' if len(st) == 0 else st[:15]
    st = re.sub('^[.]|[.]$', '', st)
    st = st if len(st) > 2 else st + "".join([st[-1] for i in range(3-len(st))])
    return st

isalnum()은 isalpha+isdigit를 한 것이다. 위 코드를 짜면서 다시 한번 배운것은 우선 replace랑 remove는 둘다 특정 인덱스의 값을 지울 수 없고, 전체 또는 맨앞의 것만 바꾼다. 따라서 문자열을 수정할 때는 신중하게 해야한다.